If it's not what You are looking for type in the equation solver your own equation and let us solve it.
36x-2x^2=0
a = -2; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·(-2)·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*-2}=\frac{-72}{-4} =+18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*-2}=\frac{0}{-4} =0 $
| 2x+8=12+× | | 3^-7*3^x=27 | | 18/5=f-32/9 | | 19x^2=15x+5 | | 4(2y-5)=42 | | 4^2-6p=0 | | 12+4x=x+15 | | -7+x=27 | | 12x+(15x/2)=99 | | 1x+5*5=9 | | 1x+5²=9 | | -73+3x=15=11x | | 9-4x=2x=6 | | 3x=-5+1 | | e/9=3=3 | | 2+10i×4i+5+2+10i=0 | | 3x=10x-15 | | (a×2)+(a×2)+(3/4)à=67500 | | 4+49=21x+8 | | 9x=−12 | | x10x=3 | | 25+x^2+26=x-1 | | x^2-6,25=0 | | (x-1)+2(x-3)=x-5 | | 7=2y+3=15 | | 4x+8=62-6x | | x¨2-5x+6=0 | | 7/x=14/21 | | Z^4=-2+2i | | 3(2.10i-4i+5)=0 | | 3x-1=10x-15 | | 10x-8=x+9 |